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x^2-360x+11200=0
a = 1; b = -360; c = +11200;
Δ = b2-4ac
Δ = -3602-4·1·11200
Δ = 84800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{84800}=\sqrt{1600*53}=\sqrt{1600}*\sqrt{53}=40\sqrt{53}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-360)-40\sqrt{53}}{2*1}=\frac{360-40\sqrt{53}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-360)+40\sqrt{53}}{2*1}=\frac{360+40\sqrt{53}}{2} $
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